segunda-feira, 21 de outubro de 2013

35º Dia de aula - Matemática

Sorocaba, 21 de outubro de 2013

Exercícios

1)      Dados log2=0,301 | log3=0,477 | log5=0,699 | log7=0,845. Calcule:

a)      Log15=log3+log5
              0,477+0,699
Log15=1,176

b)      Log14=log3+log5
              0,301+0,845
Log15=1,146

c)       Log42=log7+log3+log2
              0,845+0,301+0,301
Log42=1,623

d)      Log210=log2+log3+log5+log7
              0,301+0,477+0,699+0,845
Log210=2,322

e)      Log1,5=log15:log10
              1,176:1
Log15=1,176
 
f)       Log0,6=log6-log10
       6     0,778-1
      10
Log0,6=-0,222

g)      Log5+log50+log200=
 0,699+1,699+2,301
Log15=4,699

h)      Log0,15-log4,2=

2)      Dado o sistema de equação: logX-logY=log3. Calcule t, com y2=x
                                                    x+2y=15                                        3t=9
x=3 -> x=3y                                3y+2y=15                                      t=2
y                                                  5y=15
                                                    x=3y
                                                    x=3.3
                                                    x=9