Sorocaba,
21 de outubro de 2013
Exercícios
1)
Dados log2=0,301 | log3=0,477 |
log5=0,699 | log7=0,845. Calcule:
a)
Log15=log3+log5
0,477+0,699
Log15=1,176
b)
Log14=log3+log5
0,301+0,845
Log15=1,146
c)
Log42=log7+log3+log2
0,845+0,301+0,301
Log42=1,623
d)
Log210=log2+log3+log5+log7
0,301+0,477+0,699+0,845
Log210=2,322
e)
Log1,5=log15:log10
1,176:1
Log15=1,176
f)
Log0,6=log6-log10
6 0,778-1
10
Log0,6=-0,222
g)
Log5+log50+log200=
0,699+1,699+2,301
0,699+1,699+2,301
Log15=4,699
h)
Log0,15-log4,2=
2)
Dado o sistema de equação:
logX-logY=log3. Calcule t, com y2=x
x+2y=15 3t=9
x=3
-> x=3y 3y+2y=15 t=2
y 5y=15
x=3y
x=3.3
x=9